Math, asked by rsreekanthaadhi, 4 months ago

Six years back age of Munir was 3time age of Mujib after four year age of Munir becomes twice the age of Mujib find the age of two of them​

Answers

Answered by helper07525E
0

Answer:

hwenejejjekekeop

Step-by-step explanation:

kop o3o3o3oo3o

Answered by TamannaSutradhar
0

present age of munir is 36 years and present age of mujeib is 16 years.

let the present age of muneer be x

let the present age of muneer be xin present age of mujeeb be y

ATQ

x-6=3(y-6)

x-6=3(y-6)x-3y+12=0______eqn 1

again,

x + 4 =2( y + 4)

x + 4 =2( y + 4)x - 2y - 4= 0_______eqn 2

subtracting equation 1 from 2

x - 2y - 4 - (x - 3 y + 12) = 0

x - 2y - 4 - (x - 3 y + 12) = 0x - 2y - 4 - x + 3 y - 12 = 0

x - 2y - 4 - (x - 3 y + 12) = 0x - 2y - 4 - x + 3 y - 12 = 0y-16 = 0

x - 2y - 4 - (x - 3 y + 12) = 0x - 2y - 4 - x + 3 y - 12 = 0y-16 = 0y = 16

taking y as 16 in equation 2

x - 2(16) - 4 =0

x - 2(16) - 4 =0x - 32 - 4= 0

x - 2(16) - 4 =0x - 32 - 4= 0x= 36

therefore x = 36 and y = 16

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