Question

six years before , age of mother was equal to square of her son's age. three years hence her age will be thrice the age of the son. find present ages of mother and son​

Answer 1

Answer:

Suppose, the age of the son six year before was x

∴ mother’s age six year before was x2

∴ present age of the son is (x + 6) and

present age of the mother is (x2 + 6)

Three years hence, son’s age will be (x + 9) and mother’s age will be (x2 + 9)

by given condition,

x2 + 9 = 3(x + 9)

∴ x2 - 3x + 9 - 27 = 0

∴ x2 - 3x - 18 = 0

∴ (x - 6) (x + 3) = 0

∴ x = 6 or x = -3

But age cannot be negative ∴ x ≠ -3

∴ son’s present age = x + 6 = 6 + 6 = 12 years.

mother’s present age = x2 + 6 = 36 + 6 = 42 years.

Answer 2

Step-by-step explanation:

Given Six years before, the age of mother was equal to the square of her son's age. Let the age of mother be x years and age of the son be y years. We take y = 12 since 6 yrs ago it will be 3 - 6 = -3 yrs.