Question

Six
years
ers hence a man's
age
will be three times as old
as his son. Find their
present
lages,​

Answer 1

Answer:

Also,man's age will be 3 times his son's age 6 years later. To find: Present age of son and father =? Therefore,the man's present age is 30 and the son's present age is 6.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

son’s age is 6 and father’s age is 30.

$\huge{\underline{\underline{\sf{</u><u>Given</u><u>-}}}}$

3 years ago,a man’s age was 9 times as old as his son.

Also,man’s age will be 3 times his son’s age 6 years later.

$\huge{\underline{\underline{\sf{To Find-}}}}$

Present age of son and father =?

$\huge{\underline{\underline{\sf{Solution-}}}}$

Let the son’s present age be ‘x’,man’s age be ‘y’

Then, y+6=3(x+6) and y-3=9(x-3)y+6=3(x+6) andy−3=9(x−3)

$\begin{gathered}\begin{array}{l}{y+6=3 x+18} \\ {3 x-y+18-6=0}\end{array}\end{gathered}$

3 x-y+12=0--------(1)3x−y+12=0−−−−−−−−(1)

Also, y-3=9 x-27y−3=9x−27

$\begin{gathered}\begin{array}{l}{9 x-y-27+3=0} \\ {9 x-y-24=0}\end{array}\end{gathered}$

(1)– (2) gives 3 x-y+12-9 x+y+24=03x−y+12−9x+y+24=0

$\begin{gathered}\begin{array}{l}{-6 x+36=0} \\ {6 x-36=0} \\ {6 x=36} \\ {x=6}\end{array}\end{gathered}$

from (1) y=3 x+12=3(6)+12=18+12=30y=3x+12=3(6)+12=18+12=30

Therefore,the man’s present age is 30 and the son’s present age is 6.

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