Math, asked by LizyJoseph, 8 months ago

Six years hence a man's age will be 3 times his son's age and 3 years ago he was 9 times as old as his son. Find their present ages.

Pls help me

Answers

Answered by rattans792
0

Answer:hope you understood

Step-by-step explanation:

Attachments:
Answered by maddymenon2910
0

Answer:

Step-by-step explanation:

Given:  

3 years ago,a man’s age was 9 times as old as his son.  

Also,man’s age will be 3 times his son’s age 6 years later.  

To find:  

Present age of son and father  =?

Solution:

Let the son’s present age be ‘x’,man’s age be ‘y’  

Then,  

Also,

(1)– (2) gives

from (1)

Therefore,the man’s present age is 30 and the son’s present age is 6.

This question has previously also been answered on brainless on 23 Mar 2018

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