Question

six years hence a man's age will be three times the age of his son and three years ago he was nine times as old as his son. find the present age

Answer 1

Hey!!!!!

let the age of the man be x and his son be y (in years)

Then ATQ,

(x + 6) = 3(y + 6)
=> x + 6 = 3y = 18

=> x - 3y = 12 ------- (1)

Also

(x - 3) = 9(y - 3)
=> x - 3 = 9y - 27

=> x - 9y = -24 -------(2)

Subtract (2) from (1)

=> x - 3y - (x - 9y) = 12 -(-24)

=> 6y = 36

=> y = 6 years.

Thus using y in (1)

=> x - 3(6) = 12

=> x = 30 years

Thus Father's age is 30 years and son's age is 6 years.

Hope this helps

Answer 2

Answer: hope this solution help you

Step-by-step explanation: