Math, asked by anastameembaig, 1 month ago

Six years hence a man's age will be three times the age of his son
and three years ago he was nine times as old as his son . the
present age of the man is
Ya) 28 (b) 32
(c) 30
(d) 34​

Answers

Answered by mathdude500
5

Basic Concept Used :-

Writing Systems of Linear Equations from Word Problem

1. Understand the problem.

  • Understand all the words used in stating the problem.

  • Understand what you are asked to find. ...

2. Translate the problem to an equation.

  • Assign a variable (or variables) to represent the unknown.

  • Clearly state what the variable represents.

3. Carry out the plan and solve the problem.

Let's solve the problem now!!!

\begin{gathered}\begin{gathered}\bf\: Let-\begin{cases} &\sf{present \: age \: of \: man \:  =  \: x \: years} \\ &\sf{present \: age \: of \: son =  \: y \: years} \end{cases}\end{gathered}\end{gathered}

After 6 years,

\begin{gathered}\begin{gathered}\bf\: So-\begin{cases} &\sf{present \: age \: of \: man \:  =  \: x + 6 \: years} \\ &\sf{present \: age \: of \: son =  \: y  + 6\: years} \end{cases}\end{gathered}\end{gathered}

According to statement,

Father age will be three times of son age

\rm :\longmapsto\:x + 6 = 3(y + 6)

\rm :\longmapsto\:x + 6 = 3y + 18

\bf\implies \:x = 3y + 12 -  -  - (1)

3 years ago

\begin{gathered}\begin{gathered}\bf\: So-\begin{cases} &\sf{present \: age \: of \: man \:  =  \: x - 3 \: years} \\ &\sf{present \: age \: of \: son =  \: y - 3\: years} \end{cases}\end{gathered}\end{gathered}

According to statement

Father age will be 9 times of son age

\rm :\longmapsto\:x - 3 = 9(y - 3)

\rm :\longmapsto\:x - 3 = 9y -27

\rm :\longmapsto\:x  = 9y -24

\rm :\longmapsto\:3y + 12 = 9y -24 \:  \:  \:  \:  \:  \:  \:  \:  \:  \{ \: using \: (1) \}

\rm :\longmapsto\:9y - 3y = 24 + 12

\rm :\longmapsto\:6y= 36

\bf\implies \:y = 6

On substituting y = 6 in equation (1), we get

\rm :\longmapsto\:x = 3 \times 6 + 12

\rm :\longmapsto\:x = 18 + 12

\bf\implies \:x = 30

\begin{gathered}\begin{gathered}\bf\: Hence-\begin{cases} &\sf{present \: age \: of \: man \:  =  \: 30\: years} \\ &\sf{present \: age \: of \: son =  \: 6 \: years} \end{cases}\end{gathered}\end{gathered}

Hence, option (c) is correct.

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