Question

six yrs before the age of mother was equal to square of her son's age.three years hence her age will be thrice the age of son then find the present ages of mother and son

Answer 1

Answer:

Son = 12 years

Mother = 42 years 



Explanation - 

Six years ago let the son age = x

Mother = x² 

Present ages now:

Son = x + 6

Mother = x²  + 6



3 years later:

Son = x + 6 + 3 = x + 9

Mother =  x²  + 6 + 3 =  x²  + 9

Solving x -

x²  + 9 = 3(x + 9)

x²  + 9 = 3x + 27

x²  - 3x - 18 = 0

(x - 6)(x + 3) = 0

x = 6 or x = -3

Take x = 6. As the other value is (- value)



Finding their Present age -

Son = x + 6 = 6 + 6 = 12 years.

Mother =  x²  + 6 = (6)² + 6 = 42 years.


Hence : 

Son = 12 years

Mother = 42 years