Question

sixteen grams of oxygen gas is introduced into an evacuated 10.0L flask at 77.0°L. What is the pressure in KPa in the container ? ( HINT R=0.082 AND O=16)

Answer 1

Answer:-

Mass of Oxygen in grams (m) = 16 g

Molar mass of Oxygen (M) = 16(2) = 32 g/mol.

Temperature (T) = 77 ° C = 350.15 ° K

R (Gas Constant) = 0.082 L* atm/K*mol.

Volume (V) = 10 L

Using Ideal Gas Equation,

→ PV = nRT. (Here , n = number of moles)

→ (P)(10) = (m/M)*(0.082)(350.15)

(Since, number of moles = mass in grams/molar mass)

→ 10P = (16/32)*(0.082)(350.15)

→ P = 459.3/10

→ P = 45.93 atm.

→ P = 45.93*(101.3)

→ P = 4652.7 kPa.