Math, asked by sahil2526, 1 year ago

Sixteen players P1, P2,......, P16 play in a tournament. They are divided
into eight pairs at random. Form each pair a winner is decided on the
basis of a game played between the two players of the pair. Assuming
that all the players are of equal strength, the probability that exactly one
of the two players P, and P, is among the eight winners is​

Answers

Answered by toobaafzal44
0

Answer:

probability of players:- ⅛

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