Question

Sixty four small drops of water of 4 mm radius and of the same charge coalesce to form a large

drop. Compare the surface charge density of a small drop with that of the large one.​

Answer 1

Answer:

Formulae:

σ

big

σ

small

=

Q

q

×

r

2

R

2

=

nq

q

×

r

2

(n

3

1

r)

2

=n

−

3

1

=64

−

3

1

=

4

1

hence the ratio is 1:4