Question

sixty four solid iron spheres, each of radius r and surface area S are melted to form a sphere with surface area S. Find the ratio of S and S.​

Answer 1

No. of rods= 64

radius each= r

surface area of small sphere(s) = S1

surface area of big sphere = S2

let radius of big sphere be R

so,

n 4/3πr³= 4/3πR³(law of conversation of mass)

n= R³/r³

answer:

ratio is R³/r³

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