Sixty four solid iron spheres, each of radius r and surface area S are melted to form a sphere with surad S. Find the ratio of S and S'.
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volume of 64 iron spheres=volume of new sphere
64×4/3πr³=4/3πr'³
64r³=r'³
³√64r³=³√r'³
4r=r'
r'=4r
ratio of s and s'
s/s'=4πr²/4πr²
=(r²)/(4r')²
=r²/16r²
=1/16
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