size of an image of an object by a mirror (f=20cm) is reduced *by* 1/3 of its height. At what distance has the object been placed from the mirror? Find the nature of the image.
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Correct option is
A
80 cm
Using magnification formula,
m=−
u
v
=
3
1
⇒v=−
3
u
From mirror formula,
v
1
+
u
1
=
f
1
From above two equations,
−u
3
+
−u
1
=
20
1
u=−80 cm
So, the object is placed at a distance of 80cm in front of the mirror.
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