Chemistry, asked by balaji062508, 7 months ago

size of first orbit0/5of hydrogen atom is 5.29nm,the size of second orbit of He+ is​

Answers

Answered by srushvraj162006
0

Given that a

0

=5.29×10

−11

meter

we know that for any hydrogen atom like system r

n

=

Z

a

0

n

2

so for He

+

i.e Z=2 and its second orbit i.e n=2 so r

2

=

2

4a

0

=2a

0

=2×5.29×10

−11

m=10.58×10

−11

m

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