size of first orbit0/5of hydrogen atom is 5.29nm,the size of second orbit of He+ is
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Given that a
0
=5.29×10
−11
meter
we know that for any hydrogen atom like system r
n
=
Z
a
0
n
2
so for He
+
i.e Z=2 and its second orbit i.e n=2 so r
2
=
2
4a
0
=2a
0
=2×5.29×10
−11
m=10.58×10
−11
m
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