size of image of an object by a lens having focal length of 20cm is observed to be magnified towards 4 third of its size what is the nature of the image and the lens at what distance the object has been placed from the lens
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Given Size of image of an object by a lens having focal length of 20cm is observed to be magnified towards 4 third of its size what is the nature of the image and the lens at what distance the object has been placed from the lens
Given f = 20 cm
Magnification = m = v/u
= 4/3 = v/u
So 3 v = 4 u
So v = 4 u / 3
We know that 1/f = 1/v + 1/u
1/f = 3/4u + 1/u
7u/4u^2
1/f = 7/4u
4u = 7f
Or u = 7f / 4
So u = 7/4 (20)
Or u = 35 cm
So object distance is 35 cm
Now 1/v = 1/20 - 1/35
1/v = 3/140
So v = 140/3
Now image is a virtual image.
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