Physics, asked by priyaswaminathan2004, 1 year ago

Size of the image of an object by a concave lens of focal length 20cm is observed to be reduced to 1/3rd of its size. Find the distance of the object from the lens.

Answers

Answered by Vijay03147
0

I hope this will help you

Attachments:

priyaswaminathan2004: Thanku soo much.
priyaswaminathan2004: R u 10th standard
Vijay03147: yes
priyaswaminathan2004: Ok.
priyaswaminathan2004: R u a tamil or hindi student
Vijay03147: hindi
priyaswaminathan2004: Okay
Answered by nilesh102
0

hi mate,

Solution: object distance from the optical centre of the lens is 40cm.

explanation : focal length of concave lens , f = -20cm

a/c to question,

size of image = 1/3 × size of object.

so, magnification , m = 1/3

we know, magnification of lens , m = v/u

so, v/u = 1/3

so, v = u/3 ........(1)

now applying lens maker formula,

1/v - 1/u = 1/f

or, 1/(u/3) - 1/u = 1/-20

or, 3/u - 1/u = 1/20

or, 2/u = 1/-20 cm

or, u = -40 cm

hence, object is placed 40cm from the pole of concave lens.

i hope it helps you.......

.

Similar questions