Physics, asked by sharanabasavame6000, 1 year ago

Size of the image of an object by a concave lens of focal length 20 cm is observed reduced to 1/3rd if it’s size find distance of the object from the lens

Answers

Answered by shivi14151
1

m=f-u/f and for concave lens f is negative sign where m is 1/3 then you will find -40 cm mark this is brainlist ans

Answered by nilesh102
1

hi mate,

Solution: object distance from the optical centre of the lens is 40cm.

explanation : focal length of concave lens , f = -20cm

a/c to question,

size of image = 1/3 × size of object.

so, magnification , m = 1/3

we know, magnification of lens , m = v/u

so, v/u = 1/3

so, v = u/3 ........(1)

now applying lens maker formula,

1/v - 1/u = 1/f

or, 1/(u/3) - 1/u = 1/-20

or, 3/u - 1/u = 1/20

or, 2/u = 1/-20 cm

or, u = -40 cm

hence, object is placed 40cm from the pole of concave lens.

i hope it helps you.......

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