Size of the image of an object by a concave lens pf focal length 20 cm is observed to be reduced to 1/3rd of the size .Find the distance of the object from the lens
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h'/h = v/u
1/3h/h =v/u
v = u/3
from lens formula
1/v - 1/u = 1/f
1/u/3 - 1/u = 1/f
3/u - 1/u = 1/-20
u = -40 cm..
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Answer:
Explanation:
Given:
F=-20
M=-1/3
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