Size variation between N3+and Na+andMg2+andAl3+andO2-andF-
Answers
Answered by
3
☺☺
⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐
☺_______☺_______☺_______☺________☺_______☺
....................................................................
-ve sign means more of electrons and +ve sign means lack of electrons.
Here N 3- with atomic no. 7 has 7+3= 10 electrons
O 2- witha tomic no. 8 has 8+2 = 10 electrons
F - with atomic no. 9 has 9+1= 10 electrons
Na + with atomcatomic no. 11 has 9-1= 10 electrons
Mg 2+ with atomcatomic no. 12 has 12-2= 10 electrons
Al 3+ with atomcatomic no. 13 has 13-3= 10 electrons
Since all these ions have 10 electrons in their shell therefore these are isoelectronic speicies
The more + the charge, the smaller the ionic radius. Remember that - means adding electrons.
These electrons go in the outermost shells. Also, when an atom loses electrons, it clings ever more tightly to the ones it has left, further reducing the ionic radius. therefore the order of ionic radii will be →
AL 3+ Mg 2+ Na + F - O 2- N 3-
(increasing order)
..................................................................
☺______☺_______☺_______☺________☺_______☺
glad to help you ☺
hope you liked it !! ☺☺
thank's
☺☺
⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐
☺_______☺_______☺_______☺________☺_______☺
....................................................................
-ve sign means more of electrons and +ve sign means lack of electrons.
Here N 3- with atomic no. 7 has 7+3= 10 electrons
O 2- witha tomic no. 8 has 8+2 = 10 electrons
F - with atomic no. 9 has 9+1= 10 electrons
Na + with atomcatomic no. 11 has 9-1= 10 electrons
Mg 2+ with atomcatomic no. 12 has 12-2= 10 electrons
Al 3+ with atomcatomic no. 13 has 13-3= 10 electrons
Since all these ions have 10 electrons in their shell therefore these are isoelectronic speicies
The more + the charge, the smaller the ionic radius. Remember that - means adding electrons.
These electrons go in the outermost shells. Also, when an atom loses electrons, it clings ever more tightly to the ones it has left, further reducing the ionic radius. therefore the order of ionic radii will be →
AL 3+ Mg 2+ Na + F - O 2- N 3-
(increasing order)
..................................................................
☺______☺_______☺_______☺________☺_______☺
glad to help you ☺
hope you liked it !! ☺☺
thank's
☺☺
Similar questions
Computer Science,
7 months ago
English,
7 months ago
English,
1 year ago
World Languages,
1 year ago