Skater slides over the ice with a uniform acceleration of 1.5 m.s2
within a distance of 15 m, its velocity reaches 20 m/s calculate the final
velocity of skater.
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Answered by
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Answer:
u = 20ms-¹
v = u + 2 as
v = 20 + 2×1.5×15
v = 20 + 45
v = 65ms-¹
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