sketch a graph of the function f(x) = x3 + 2x2 – 8x.
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Answer:
x < - 4 f(x) is -ve
-4 < x < 0 f(x) is + ve
0 < x < 2 f(x) is -ve
x > 2 f(x) is +ve
Step-by-step explanation:
f(x) = x³ + 2x² - 8x
= x(x² + 2x -8)
= x( x² + 4x - 2x -8)
=x(x(x+4) -2(x+4))
=x(x-2)(x+4)
Zeroes are
0 , 2 , - 4
x < - 4 f(x) is -ve
-4 < x < 0 f(x) is + ve
0 < x < 2 f(x) is -ve
x > 2 f(x) is +ve
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