Question

Sketch graph (y-t) for an object in free fall from a height Δy above ground level

Answer 1

Answer:

Above ground level from the object if graph lies between the two objects above the ground level from x and y

Answer 2

The graph will be a parabolic curve shown in the attached fig .

Explanation :

Since object is falling freely from a height of Δy .

So , at some height y , distance travelled will be :

=Δy - y

So, on using the 2nd equation of motion we have :

$\Delta y - y = ut + \frac{1}{2}at^2$  

Here, since the body is falling freely so initial velocity will be 0.

And a = -g

So,$\Delta y - y = -\frac{1}{2}gt^2$

Or,$y = \Delta y + \frac{1}{2}gt^2$

$(y -t) = \Delta y +\frac{1}{2}gt^2 - t$

Or,$(y-t)= \frac{1}{2}gt^2 + (\Delta y - t )$

It is a quadratic equation so graph will be parabola.