sketch proper fig x-y-2 l (x 3) = 5√6 . l (xcy) = 2 √6 I then find y3
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Solution:
Short Trick∶
⇒ x + y = 3
⇒ Let x = 2 and y = 1, then
⇒ x3 – y3 = 23 – 1 = 8 – 1 = 7
Detailed Solution∶
Given, (x + y) = 3 and xy = 2
As we know,
⇒ (x + y)2 – (x – y)2 = 4xy
⇒ 32 – (x – y)2 = 4 × 2
⇒ (x – y)2 = 9 – 8 = 1
⇒ (x – y) = √1 = 1
As we know,
⇒ x3 – y3 = (x – y) (x2 + y2 + xy)
⇒ x3 – y3 = 1 × [(x + y)2 – xy]
⇒ x3 – y3 = 32 – 2 = 9 – 2 = 7
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Step-by-step explanation:
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