Question

Sketch the microstructure of 0.2% c steel. Calculate %pearlite % cementite, % proeutectoid ferrite and % total ferrite.

Answer 1

❇ Your answer⬇⬇

The structure would consist of proeutectoid ferrite and pearlite. Assume solubility of carbon in

ferrite is negligible. Refer to phase diagram to get % Pearlite in 0.2% carbon steel =

$\frac{0.2 - 0}{0.8 - 0} \times 100 = 25$

Balance 75% is proeutectoid ferrite. % Cementite =

$\frac{0.2 - 0}{6.67 - 0} \times 100 = 3 \: persent$

3% and total ferrite = 97%.

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