Math, asked by deepak26bit, 6 months ago

SKILL TEST 2
Tick (✓) the correct answer:
1. Nitin was counting down from 31. Sumit was counting upwards
the numbers star
ting from 1 and he was calling out only the odd
numbers. What common number will they call out at the same
time if they were calling out at the same speed?
(a) 19
(b) 20
(c) 21
(d) 22​

Answers

Answered by amitnrw
0

Given : Nitin was counting down from 31.

Sumit was counting upwards from 1 and was calling out only odd  numbers

To Find : common number they call out at the same time

(a) 19

(b) 20

(c) 21

(d) 22​

Solution:

1st called

31  and  1

Difference  = 30

Now Nitin called = 31 - 1 = 30

and Sumit called = 1 + 2 = 3

Difference = 27

on 1st calling  Difference = 30

on 2nd calling difference = 27

on 3rd calling difference = 24  and so on

0 = 30 + (n - 1)(-3)

=> n = 11

11th Calling

on 1st calling number was 31

31 + (11 - 1)(-1)  = 31 - 10 = 21

on 11 th calling  number  = 21

or  1  + (11  - 1)*2  = 21

Hence  common number called = 21  at same time

31 1

30 3

29 5

28 7

27 9

26 11

25 13

24 15

23 17

22 19

21 21

common number called = 21   at same time

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