Question

Skip count by 6000 starting from 12000 until you reach 30000.....

Answer 1

Counting Numbers

This is a very simple questions of addition, where the first number is 12000 and the next numbers are found by adding 6000 consecutively.

• First number = 12000
• Second number = 12000 + 6000 = 18000
• Third number = 18000 + 6000 = 24000
• Fourth number = 30000

The required result is given by

12000, 18000, 24000, 30000.

Note:

• If you understand arithmetic progression, you will see that the common difference here given is 6000 and the first term is 12000, the last term is 30000.
• However simply proceed with addition.