slab of glass of thickness 6 cm and refractive index new is equals to 1.5 is placed in front of a concave mirror as shown in the figure if the radius of curvature of the mirror is 40 cm and the reflected image coincides with the object then the distance of the object from the mirror is
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The distance of the object from the mirror is 40 cm.
Explanation:
Shift due to glass slab:
t ( 1 - 1/μ) = 6 ( 1 - 2/3) = 6 (1/3) = 2 cm
Since radius of curvature = 40 cm
Object must be placed on a distance of 42 cm
so that due to shift the image and object will be at 40 cm and both coincide.
Hence the distance of the object from the mirror is 40 cm.
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