Question

slant height of right pyramid where base is 12 cm and height is 8 cm​

Answer 1

Answer:

base is 12 cm and height is 8 cm

For equilateral triangle the centroid is,

$r = \frac{a}{ \sqrt{3} } = \frac{8}{ \sqrt{3} }$

So slant height is,

$l = \sqrt{ {r}^{2} + {h}^{2} }$

$l = \sqrt{ \frac{64}{3} + 64 } = \sqrt{ \frac{64 \times 4}{3} } = \frac{16}{ \sqrt{3} }$

Answer 2

Answer:

Step-by-step explanation:

hypotenus^2 = hight^2 + base^2

hypotenus^2 = 12^2 + 8^2

hypotenus^2 = 144 + 64

hypotenus^2 = 208

hypotenus^2 = root 208