slips, i.e. one number on one slip, and
put in a box. Amina picks a slip from the
box without looking at it. What is the
probability that the slip bears an odd
number?
4. Numbers 1 to 20 are written on separate
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total number of slips = 20
number of odd numbered slips = 10
Probability of drawing an odd numbered slip = ?
we know that P(E) = Number of outcomes favorable to the event divided by Total number of possible outcomes of the event
hence P(drawing a slip bearing odd number) = number of odd numbered slips divided by total number of slips
= 10/20
=1/2
hence the probability of drawing a slip which bears an odd number is 1/2
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