Slope of a line ax+by+c=0 if ?
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Answered by
23
Hi friend!!
Given, line equation ax+by+c=0
→by=-ax-c
=y=(-a/b)x-(c/b)
Comparing the equation with y=mx+c
slope of the given line is -a/b
I hope this will help you ;)
Given, line equation ax+by+c=0
→by=-ax-c
=y=(-a/b)x-(c/b)
Comparing the equation with y=mx+c
slope of the given line is -a/b
I hope this will help you ;)
Answered by
12
Given equation is ax + by + c = 0
We know the other form of the equation :- y = mx+C
Where
m = slope
C = y-intercept
Divide the given equation by b, we get
(a/b)x + y + (c/b)=0
Y = -((a/b)x+(c/b))
Relating this to the slope form equation, we get
m = -(a/b)
C = -(c/b)
★ So, the slope then slope of the line equation ax+by+c = 0 is -a/b
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