Question

slope of graph y = tan x drawn between y and x,at x = π/4​

Answer 1

y = tan x

dy/dx = sec²x

y' = sec²x

when x = π/4, tanπ/4 = 1

so, at the point (π/4,1)

slope is sec²x = sec²π/4 = 2 =m

so equation is y= mx+c

1 = 2π/4 +c

c= 1- 2π/4 = (2-π)/2

so, tangent equation is

y = 2x + (2-π)/2

Answer 2

Answer:

2

Explanation:

y = tan x

y' = sec² x

= sec² π/4

= 2 ..... ( sec π/4 = √2)