Slope of line joining points (5,3) and (k²,k+1) is 1/2, then k is?
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m=( y2 - y1)/(x2 - x-1)
1/2 = (k - 2)/(k^2 - 5)
k^2 - 5 = 2k - 4
k^2 - 2k - 1 0
k^2 - 2x + 1 - 2 =0
(k - 1)^2 - (sqrt2)^2 = 0
{k - (1+ sqrt 2 )}{k - (1 - sqrt2)}= 0
k= 1 + and - sqrt 2
option b is right
using
(a - b)^2 = a^2 + b^2 -2ab
a^2 - b^2'= (a+ b )(a - b)
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