Question

slope of one line of pair of lines 2x^2 + 3xy + ky^2 =0 is 2 thenthe value of k​

Answer 1

Answer:

${( \sqrt{2 } x + \frac{3}{2 \sqrt{2} } y)}^{2}$

$= 2 {x}^{2} + 3xy + \frac{9}{8} {y}^{2}$

$so \: k = \frac{9}{8}$

Answer 2

Value of k is 9/8
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