slope of straight line 4x+3y=1
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4x+3y=1, slope of this line is solved by method of derivative dy/dx called slope.
then,
4x+3y=1
4(1)+3dy/dx=0
4+3dy/dx=0
3dy/dx=-4
dy/dx=-4/3
so slope of line is -4/3
then,
4x+3y=1
4(1)+3dy/dx=0
4+3dy/dx=0
3dy/dx=-4
dy/dx=-4/3
so slope of line is -4/3
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