Slope of straight line in fig 2 -1.2×10k .what is the activation energy of reavtion
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»»»Notice that when the Arrhenius equation is rearranged as above it is a linear equation with the form y = mx + b; y is ln(k), x is 1/T, and m is -Ea/R. The activation energy for the reaction can be determined by finding the slope of the line.
»»»Step 1: Convert temperatures from degrees Celsius to Kelvin. T = degrees Celsius + 273.15. T1 = 3 + 273.15. ...
Step 2 - Find Ea ln(k2/k1) = Ea/R x (1/T1 - 1/T2) ln(7.1 x 10-2/8.9 x 10-3) = Ea/8.3145 J/K·mol x (1/276.15 K - 1/308.15 K) ...
Answer: The activation energy for this reaction is 4.59 x 104 J/mol or 45.9 kJ/mol.
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