Question

slope of tangent to the curve y=3x^2+3sinx at x=0​

Answer 1

Answer:

-3

Step-by-step explanation:

Given curve is    $y =3x^{2} +3sinx$

Slope of the tangent = $\frac{dy}{dx}$ = $6x- 3cosx$

                                          = 6(0) - 3cos(0)       [∵x = 0.]

                                          = -3.