Question

Slope of the curve y= 4x² at x = 1 is​

Answer 1

Answer:

Let f(x)=4x2

∴f′(-1)=limh→0

f(-1+h)-f(-1)

h

=limh→0

4(1-2h+h2)-4

h

=limh→04(-2+h)=4(-2)

=- 8

f′(-1)=-8 is the slope of tangent at point (-1,4) of the curve y=4x2.

Answer 2

Answer:

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