Question

Slope of the tangent to the curve xy = 6 at (1,0)

Answer 1

Answer:

We have,

xy=6

Now, differentiate w.r.t x, we get

y+xdxdy=0

xdxdy=−y

dxdy=−xy

Put x=1,y=6

So,

dxdy(1,6)=−16

dxdy(1,6)=−6

Therefore,

The slope of the tangent of the curve 

=−6

And the slope of the normal the curve

=−m1

=−−61

=61