Question

slope of the tangent to the curve y= 5-10x^2 at the point (-1 , -5) is ______
(10, -10, 20, -20)​

Answer 1

Answer:

2

Step-by-step explanation:

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Answer 2

Answer:

The answer is 20

Step-by-step explanation:

Given curve is $y=5-10x^2$

                    $\Rightarrow \dfrac{dy}{dx}=0-10(2x)=-20x$

Now to get slope of tangent at $(-1,-5)$ replace x by -1 in dy/dx

Therefore required slope of tangent  $=-20(-1)=20$