Math, asked by bhanuprakashreddy23, 9 months ago

slope of x^3-4x^2y+6xy^2-3y^3=0 at (1,1)​

Answers

Answered by Anonymous
11

Step-by-step explanation:

(2x)^3-y^3-6xy(2x-y)

(2x-y)(4x^2 +2xy+y^2) - 6xy(2x-y)

(2x-y)-[4x^2 +2xy+y^2 - 6xy]

(2x-y)(4x^2-4xy+y^2)

(2x-y)[(2x)^2-2x2xy+y^2]

(2x-y)(2x-y)^2

(2x-y)^3

Answered by Anonymous
1

Answer:

(2x)³-y³-6xy(2x-y)

(2x-y)(4x² +2xy+y²) - 6xy(2x-y)

(2x-y)-[4x²+2xy+y² - 6xy]

(2x-y)(4x²-4xy+y²)

(2x-y)[(2x)²-2x2xy+y²]

(2x-y)(2x-y)²

(2x-y)³

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