Question

slove 5(p+3)=4(2p+1)​

Answer 1

Given: $5(p+3)=4(2p+1)$

We have to solve the equation$5(p+3)=4(2p+1)$.

For this, we have to multiply the left-hand side bracket by $5$and the right-hand side bracket by $4.$

And then simplify the equation.

We have, $5(p+3)=4(2p+1)$

Now,

=> $5(p+3)=4(2p+1)$

$=>5p+15=8p+4\\=>15-4=8p-5p\\=>11=3p\\=>p=\frac{11}{3} \\\\=>p=3.66$

We get, $p=3.66$

Hence, the solution of the equation will be$3.66$.

Answer 2

We are given an equation 5(p+3)=4(2p+1)​

We have to solve the equation for p

First, we will open the brackets

$5(p+3)=4(2p+1)\\5p+15 = 8p +4$

Now, we will rearrange the equation

$8p-5p= 15-4\\3p=11\\p=\frac{11}{3}$

Therefore, the value of p will be 11/3