Question

Slove and verify your result: 5(x-1)+2(x+3)+6=0​

Answer 1

given

• 5(x-1)+2(x+3)+6=0

solution

• 5(x-1)+2(x+3)+6=0

• first step 5 and 2 multiplie in bracket

• $5x - 5 + 2x + 6 + 6 = 0$
• adition

• $7x + 12 - 5 = 0$
• subscrate

• $7x + 7 = 0$
• take common 7

• $7(x + 1) = 0 \\ \\ x + 1 = 0 \\ \\ x = - 1$

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I hope it helps you

Answer 2

Answer:

5(x-1)+2(x+3)+6=0

5x-5+2x+6+6=0

7x+7=0

7x=(-7)

x=(-7)÷7

x=(-1)