slove any1 question from these.
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(1) p(e)= n(e)/ n(s)
n(s)=200
p(e)=45/200
(2). p(e)= 35/200
n(s)=200
p(e)=45/200
(2). p(e)= 35/200
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If 0 tail comes then there will be 3 heads.
If 1 tail comes then there will be 2 heads.
If 2 tails come then there will be 1 head.
If 3 tails come then there will be 0 head.
p(at least two heads)=no. of three heads +no. of two heads/total outcomes
= ( 35 +45)/200
= 80/200
=2/5.
p(all heads)=no. of three heads/total outcomes
= 35/200
=7/40.
If 1 tail comes then there will be 2 heads.
If 2 tails come then there will be 1 head.
If 3 tails come then there will be 0 head.
p(at least two heads)=no. of three heads +no. of two heads/total outcomes
= ( 35 +45)/200
= 80/200
=2/5.
p(all heads)=no. of three heads/total outcomes
= 35/200
=7/40.
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