Math, asked by Anonymous, 1 year ago

slove any1 question from these.

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Answers

Answered by Dany0001
5
(1) p(e)= n(e)/ n(s)
n(s)=200
p(e)=45/200

(2). p(e)= 35/200
Answered by Anonymous
0
If 0 tail comes then there will be 3 heads.

If 1 tail comes then there will be 2 heads.

If 2 tails come then there will be 1 head.

If 3 tails come then there will be 0 head.

p(at least two heads)=no. of three heads +no. of two heads/total outcomes

= ( 35 +45)/200

= 80/200

=2/5.

p(all heads)=no. of three heads/total outcomes

= 35/200

=7/40.
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