Slove for the real value of x 4^x +6^x =9^x
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Step-by-step explanation:
taking log both sides
2xlog2 + xlog6 = 2xlog3
2xlog2 + x(log2 + log3) = 2xlog3
3xlog2 = xlog3
3log2 = log3
thus we have no real values of x
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