Question

slove for x if log (x-1) +log (x+1) = log 1
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Answer 1

Answer:

$\log _{10}\left(x-1\right)+\log _{10}\left(x+1\right)=\log _{10}\left(1\right)\quad :\quad x=\sqrt{2}\quad \left(\mathrm{Decimal}:\quad x=1.41421\dots \right)$

Step-by-step explanation:

$\log _{10}\left(x-1\right)+\log _{10}\left(x+1\right)=\log _{10}\left(1\right)$

$\left(x-1\right)\left(x+1\right)=1$

$x=\sqrt{2},\:x=-\sqrt{2}$

$x=\sqrt{2}$