Question

slove for X $\frac{1}{a} + \frac{1}{b} + \frac{1}{x} = \frac{1}{abx}$

Answer 1

Step-by-step explanation:

Here's your answer

Hope it helps

please follow me

mark it as brainliest

if you have more questions

send them on my Instagram

ID is on my profile

Answer 2

(1-ab)/(b+a).

Step-by-step explanation:

Given:

$\dfrac{1}{a} + \dfrac{1}{b} + \dfrac{1}{x} = \dfrac{1}{abx}$

To find:

value of x

Solution:

$\frac{1}{a} + \frac{1}{b} + \frac{1}{x}=\frac{1}{abx}\\\\\frac{1}{a} + \frac{1}{b}=\frac{1}{abx}-\frac{1}{x} \\ \\ \frac{b + a}{ab} = \frac{1 - ab}{abx} \: \: [\text{By Taking L.C.M}] \\\\ \frac{b + a}{\cancel{ab}} = \frac{1 - ab}{\cancel{ab}x} \\ \\ x(b + a) = 1 - ab \: [\text{By Cross Multiple}] \\ \\ x = \frac{1 - ab}{b + a}$

Therefore, The required value of x is (1-ab)/(b+a).

Important Note

This question is related with equation with one variables. To simplify these types of questions you should know some basic rules.

i) sign of any no. or variable will change

between equal (=) like + will change in - and multiple will change in division.

ii) We can simply eliminate the no. from one side to another side if they are in multiple or have common factor.