Math, asked by hubnadaun, 5 months ago

slove it 1*1 ,2*2 ,3*3, 4*4, 5*5, 6*6, 7*7 , 8*8, 9*9 ,10*10 .......................................... 50*50​

Answers

Answered by Anonymous
3

Answer:

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12

= 12

= 12

= 12

= 12

= 12jwjajahahauuayayayayayauaya

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12

= 12

= 12

= 12

= 12

= 12

= 12

= 12

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12

= 12

= 12

= 12

= 12

= 12

= 12

= 12

= 12

babahahaiauayua

= 12

= 12

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