Math, asked by nagasri1776381, 9 months ago

slove it.....................​

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Answered by anika107695
15

Answer:

(i)  \\  (3 {x}^{2}  - 2x) \div x \\  ⇒ \frac{3 {x}^{2} - 2x }{x}  \\  ⇒\frac{x(3x - 2)}{x}  \\  ⇒3x - 2 \\  \\  Answer: \: 3x - 2. \\  \\

(ii) \\ (5 {a}^{3} b - 7a {b}^{3} ) \div ab \\  ⇒  \frac{5 {a}^{3} b - 7a {b}^{3}  }{ab}  \\  ⇒ \frac{ab(5 {a}^{2} - 7 {b}^{2})  }{ab}  \\⇒  5 {a}^{2}  - 7 {b}^{2}  \\  \\ Answer: \: 5 {a}^{2}  - 7 {b}^{2} . \\  \\

(iii) \\ (25 {x}^{5}  - 17 {x}^{4} ) \div 5 {x}^{3}  \\  ⇒  \frac{(25 {x}^{5}  - 17 {x}^{4}) }{5 {x}^{3} } \\  ⇒  \frac{ {x}^{3}(25 {x}^{2} -17x)  }{5 {x}^{3} }  \\  ⇒ \frac{25 {x}^{2}  - 17x}{5 }  \\  \\ Answer: \:  \frac{25 {x}^{2} - 17x }{5} . \\  \\

(iv) \\ (4 {l}^{5}  - 6 {l}^{4}   + 8 {l}^{3} ) \div 2 {l}^{2}  \\ ⇒ \frac{4 {l}^{5} - 6 {l}^{4}  + 8 {l}^{3}  }{2 {l}^{2} } \\  ⇒ \frac{2 {l}^{2} (2 {l}^{3} - 3 {l}^{2}   + 4l) }{2 {l}^{2} }  \\  ⇒2 {l}^{3}  - 3 {l}^{2}  + 4l \\  \\ Answer: \: 2 {l}^{3}  - 3 {l}^{2}  + 4l. \\  \\

(v) \\ 15( {a}^{3} {b}^{2}   {c}^{2}  -  {a}^{2}  {b}^{3}  {c}^{2}  +  {a}^{2}  {b}^{2}  {c}^{3} ) \div 3abc \\  ⇒  \frac{15( {a}^{3}  {b}^{2} {c}^{2}   -  {a}^{2}  {b}^{3}  {c}^{2} +  {a}^{2}  {b}^{2} {c}^{3} )  }{3abc}  \\  ⇒ \frac{15a bc( {a}^{2}bc - a {b}^{2}  c + abc^{2}) }{3abc}  \\  ⇒5 {a}^{2} bc - 5a {b}^{2} c + 5ab {c}^{2}  \\  \\ Answer: \: 5 {a}^{2} bc - 5a {b}^{2} c + 5ab {c}^{2} . \\  \\

(vi) \\ (3 {p}^{3}  - 9 {p}^{2} q - 6p {q}^{2} ) \div ( - 3p) \\  ⇒ \frac{3 {p}^{3}  - 9 {p}^{2}q - 6p {q}^{2}  }{ - 3p}  \\  ⇒ \frac{ - 3p(3pq -  {p}^{2}  + 2 {q}^{2}) }{ - 3p} \\   ⇒ 3pq -  {p}^{2}  + 2 {q}^{2}  \\  \\ Answer: \: 3pq -  {p}^{2}  + 2 {q}^{2} . \\  \\

(vii) \\ ( \frac{2}{3}  {a}^{2}  {b}^{2}  {c}^{2}  +  \frac{4}{3} a {b}^{2}  {c}^{2} ) \div  \frac{1}{2} abc \\ ⇒ \frac{ \frac{2}{3}  {a}^{2} {b}^{2}  {c}^{2} +  \frac{4}{3} a {b}^{2} {c}^{2}    }{ \frac{1}{2} abc}  \\  ⇒ \frac{abc( \frac{2}{3} abc +  \frac{4}{3}bc) }{ \frac{1}{2} abc}   \\  ⇒ \frac{ \frac{2}{3} abc +  \frac{4}{3} bc}{ \frac{1}{2} }  \\  ⇒  \frac{ \frac{2abc}{3} +  \frac{4bc}{3}  }{ \frac{1}{2} }  \\  ⇒  \frac{ \frac{2abc + 4bc}{3} }{ \frac{1}{2}  }  \\   ⇒\frac{2abc + 4bc}{3}   \times 2 \\  ⇒ \frac{4abc + 8bc}{3}  \\  \\ Answer: \:  \frac{4abc + 8bc}{3} . \:  \:  \:  \:  \\  \\  \\  \\  \\

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Answered by Jahnavi008
3

Step-by-step explanation:

hi andi meri telugu ah nenu kuda telugu neai and me intro cheppara plz

《Jahnavi 》

《10th =15yrs 》

frm telangana

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