Question

slove it ..,..,........,...............​

Answer 1

$\huge{\orange{\fbox{\green{\fbox{\mathcal{\orange{An}\blue{sw}\green{er}}}}}}}$

$\large{\orange{\fbox{\green{\fbox{\mathcal{\orange{No}\green{te}}}}}}}$

• $\orange{a^3+b^3= (a+b)(a^2+b^2-ab)}$

• $\blue{sin^2A+cos^2B=1}$

• $\green{Answer\;is\;1}$

$\large{\orange{\fbox{\green{\fbox{\mathcal{\orange{Sol}\blue{ut}\green{ion}}}}}}}$

• $\orange{\dfrac{sin^{3}\theta+cos^{3}\theta}{sin\theta+cos\theta}+sin\theta.cos\theta}$

• $\blue{\dfrac{(sin\theta+cos\theta)(sin^{2}\theta+cos^{2}\theta-sin\theta.cos\theta)}{(sin\theta+cos\theta)}+sin\theta.cos\theta}$

• $\green{\dfrac{(sin^{2}\theta+cos^{2}\theta-sin\theta.cos\theta)}{1}+sin\theta.cos\theta}$

• $\orange{1-sin\theta.cos\theta+sin\theta.cos\theta}$

• $\blue{1}$

Answer 2

$\huge{\orange{\fbox{\green{\fbox{\mathcal{\orange{An}\blue{sw}\green{er}}}}}}}$

$\large{\orange{\fbox{\green{\fbox{\mathcal{\orange{No}\green{te}}}}}}}$

$\orange{a^3+b^3= (a+b)(a^2+b^2-ab)}$

$\blue{sin^2A+cos^2B=1}$

$\green{Answer\;is\;1}$

$\large{\orange{\fbox{\green{\fbox{\mathcal{\orange{Sol}\blue{ut}\green{ion}}}}}}}$

$\orange{\dfrac{sin^{3}\theta+cos^{3}\theta}{sin\theta+cos\theta}+sin\theta.cos\theta}$

$\blue{\dfrac{(sin\theta+cos\theta)(sin^{2}\theta+cos^{2}\theta-sin\theta.cos\theta)}{(sin\theta+cos\theta)}+sin\theta.cos\theta}$

$\green{\dfrac{(sin^{2}\theta+cos^{2}\theta-sin\theta.cos\theta)}{1}+sin\theta.cos\theta}$

$\orange{1-sin\theta.cos\theta+sin\theta.cos\theta}$

$\blue{1}$