Question

slove it. it is from limits.​

Answer 1

Answer:

x=0

x-3/x-2^x

0-3/0-2^0

-3/-2^0 a^0=1

1/1

1

Answer 2

$lim_{x ->0 }( \frac{x - 3}{x + 2}) {}^{x} \: \: \\ =( \frac{0 - 3}{0 + 2} ) {}^{(0)} = ( \frac{3}{2} ){}^{0} = 1$